Wednesday, July 11, 2012

The anomalous configuration of the chromium atom and related issues

Eric Scerri
UCLA
Department of Chemistry & Biochemistry
Los Angeles, CA
In this the third of my recent chemistry postings I want to consider topic that is related to my aufbau post,
I want to think about the question of the so-called anomalous configurations that occur is some d and f-block atoms (shown in yellow in the diagram below).  


  • As with the previous posts there is a strong connection with chemistry teaching.   This is because students are often taught that the configurations of chromium and copper, in particular, show anomalies from the way that orbitals are occupied as we traverse the transition element series. 
  • Chromium is said to have a configuration of 3d5 4s1 as opposed to 3d4 4s2.  Copper atoms are said to have a configuration of 3d10 4s1 as opposed to 3d9 4s2 as might have been expected from the general trend.  
  • Now there is good spectroscopic evidence for these anomalous configurations and this is not something I am proposing to question at least not in this post.[1]
  • I want to begin to look closely at the commonly given textbook explanation for why chromium has the configuration that it has.  
  • Textbooks almost invariably claim that the configuration of 3d5 4s1 possesses a half-filled sub-shell and that this is consequently more stable than the expected configuration of 3d4 4s2
  • I think that such an explanation is not very credible but worse, that it is ad hoc in a rather literal sense of the term.  
  • Of course it may be true that the energy of the anomalous configuration is lower than that of the expected one.  After all, why else would the anomalous one be observed if that were not the case?  
  • But is it because of the much-cited half-filled sub-shell stability?  I don’t think so and if you’ll permit me I will replace that mouthful by the abbreviation hfss to stand for half-filled sub-shell from now on.  
  • To see the limitations of such an explanation we can just look at the atoms in the second transition series that also have anomalous configurations.  There are in fact six of them,
  • Nb, Mo, Ru, Rh, Pd, Ag
  • I am going to ignore palladium and silver for the moment since they have filled d-orbitals and so cannot play any role in arguments considering the role of hfss.  
  • But of the remaining four cases, only one of them, molybdenum, has a hfss and not surprisingly perhaps it lies directly below chromium in the periodic table.  
  • Clearly then the adoption of an anomalous cannot be explained in general by appealing to a hfss.  
  • Here is another way of thinking of this issue by drawing on an approach that is often used in philosophy, and which goes by the name of “necessary & sufficient conditions”. 
  • Let me illustrate this with an example from chemistry-atomic physics.  As is well known, the identity of an element can be established unambiguously by from a knowledge of the atomic number of its atoms.  Moreover the relationship runs in the opposite sense too, in that a specification of an atomic number serves to identify the element in question. 
  • A philosopher looking at this situation might say that the possession of a particular value of Z is both necessary and sufficient for the identification of any element.  
  • Let me unpack this a little further because such language is not all that familiar in chemistry and physics.  If Z = 79, for example, the element must be gold.  We say that having an atomic number of 79 is sufficient (is enough) to ensure that the element must be gold.  
  • Conversely, if the element is to count as gold, it is necessary (essential) for it to have an atomic number of 79.  
  • The relationship runs in both directions without any exceptions.  Because of this fact, we can be confident that the use of atomic number really “nails” the identity of all elements.  
  • Now let’s go back to those pesky anomalous configurations and the possession or otherwise of ‘hfss’.
  • It turns out, rather disappointingly, that the possession of a hfss is neither necessary nor sufficient for an atom to display an anomalous configuration.  
  • The reason why it is not necessary should be clear from the fact that Nb, Ru, Rh all show anomalies but none of them in fact have a hfss.   The reason why it is not sufficient is that there are cases which do have hfss and yet do not show anomalous configurations.  This is true of manganese, technetium, rhenium and bohrium all of which have d5 configurations.[2]  
  • So where does this leave the commonly found explanation for the anomaly in chromium in terms of hfss stability?  Simply put – not in a very good place.  It so happens that chromium shows both a hfss and an anomalous configuration but this is seldom generalizable.  
  • In other words, the explanation is ad hoc[3] in the literal sense of having been brought to bear at a particular place (Cr) while being powerless in more general cases.
  • So please stop inflicting it on unsuspecting young students!
  • Have I labored the point a little?  Well perhaps I have but what I am trying to do is to ask chemistry instructors to think a little more deeply and more critically about the contents of chemistry courses and the manner in which material is presented to students.
  • Finally, I have said a good deal about how not to explain the configuration in chromium or other anomalous cases but have yet to make any positive suggestions.  But that will need to wait for a future blog.  There are in fact several better approaches.



Notes
[1] The question of precisely what to regard as the ground state configuration will be taken up in a future posting.

[2] In the f-block Eu and Am have hfss configurations of f7 but don’t show anomalous configurations.

[3] Ad hoc is Latin for “to here” in the sense of an explanation imported into a particular place with little concern for whether it applies in other places or situations.  Such an explanation is of course considered to be a ‘bad thing’.  

General References
Eric Scerri, A Very Short Introduction to the Periodic Table, Oxford University Press, Oxford, 2011.
For other books please see,

A blog, or more like a rant, against the use of Le Châtelier’s Principle in learning and teaching chemistry



Eric Scerri
UCLA
Department of Chemistry & Biochemistry
Los Angeles, CA
website: ericscerri.com/


Following my recent post on the sloppy use of the aufbau principle,

I have been encouraged to try my hand at another blog on a topic in chemical education, namely the Le Châtelier Principle.
Here is a typical version of the principle that you might find in a chemistry textbook,

If a dynamic equilibrium is disturbed by changing the conditions, the position of equilibrium moves to counteract the change.

I want you to notice the use of the word “counteract” which is frequently also rendered as “oppose”, because I am going to argue that this is the root of all the problems associated with the use of this principle.  The principle is supposed to aid the student or even the expert in predicting the effect brought about by a change in conditions such as changing the total pressure on a system, or the concentration of one or more reactants or products or the temperature. 


In fact this is going to be more of a rant than a blog because I believe that this principle is more of a hindrance than a help.  The first time I ever taught a chemistry class was in a high school in London when I was standing in for another teacher and had to teach equilibrium theory and the use of the Le Ch telier Principle.  I made such a mess of the class and tied myself up in so many knots that I swore I would quit teaching immediately.  That is until I began to think more carefully about this issue and started to realize that the problem lay more with the wording in the principle rather than just with me.  


So what’s the problem?
Pretend for a moment that you are a novice student coming to this topic for the first time.  You are presented with the principle as a means of predicting the outcome of making one of three possible changes as mentioned above.  Of course you are happy to be given this guide and begin applying it to changes in pressure for example.  Let us assume we are discussing the case of the Haber reaction in which three moles of hydrogen react with one mole of nitrogen to yield two moles of ammonia.  You might visualize this mixture as being placed in a large balloon for example.  Now let’s apply the principle.  If the total pressure is increased you might be tempted to predict that the system or balloon will expand to a larger volume in order to “counteract” or “oppose” the increased pressure that is being applied in squeezing the balloon.  


But that’s wrong says the instructor
Unfortunately if you follow the letter of the principle in this way the instructor will soon tell you that you have made a wrong prediction.  Experiments show that on increasing the total pressure the equilibrium position shifts in such a way as to produce more ammonia, that is to say the equilibrium moves in the direction of a volume decrease rather than an increase. 

3 H2 (g)     +      N2 (g)       <---->       2 NH3 (g)

So what went wrong?  Well you were supposed to assume that the volume remains constant for one thing so the analogy with squashing the balloon was invalid.  But nobody tells that to the poor student.  The change that does actually occur is more a case of ‘accommodating’ the change rather than opposing it, something which leads many textbooks[i] to alter the wording of the principle to something like the following version,

If a chemical system at equilibrium experiences a change… then the equilibrium shifts to accommodate the imposed change and a new equilibrium is established.

But just a moment!  This means making a 1800 change to the original statement.  Accommodating is surely the opposite of counteracting?  If I try to push you away and you oppose my push you push me back.  If on the other hand I try to push you away and you accommodate this change you might yield to my push and fall down to the floor.  It seems rather odd that the principle needs to be rescued by substituting a word for “oppose” which in facts means the very opposite of oppose.  


So how can it be done properly?
As anyone who teaches high school or college chemistry is aware there is a amore categorical way to predict the outcome of raising or lowering the total pressure on a mixture of gases in equilibrium.  This involves setting up an expression for the equilibrium constant for the reaction and expanding the partial pressure of each gas in terms of products of mole fractions and total pressures,
  
                Kp          =               (p NH3)2
                                           (p H2)3 (p N2)

                          =             (M.F. NH3)2 (Ptotal)2
                             (M.F. H2)3 (Ptotal)3. (M.F. N2)(Ptotal)

where M.F. denotes mole fraction in each case. 

                           =                (M.F. NH3)2
                                    (M.F. H2)3 (M.F. N2)(Ptotal)2

We can now argue that since pressure changes do not alter the value of the equilibrium constant, raising Ptotal results in an increase in the ratio of ,
                            =             (M.F. NH3)2
                                   (M.F. H2)3 (M.F. N2)

which in turn implies an increase in the yield of ammonia at the expense of the mole fraction of the two reacts of hydrogen and nitrogen. 

The bottom line is that more ammonia is produced by raising the total pressure of the system.  

How about changes in concentration?
Whereas we are more or less forced to smuggle words like accommodate or alleviate into the original wording of the Le Châtelier Principle in order to make sense of what happens on raising the pressure, when it comes to changes in concentrations of reactants or products, it appears that the original word “oppose” does a perfect job in making sense of the situation.  Consider the following case in which substances A and B react together to form C and D,

A      +      B       <---->            C       +       D

If I raise the concentration of A or of B or even of both of them, the net outcome is that the equilibrium position will shift to the right and that larger concentrations of C and D will be produced.  Here the word “oppose” works fine.  As I increase the concentration of A for example the reaction responds by using up the additional A and as a result larger concentrations of C and D are formed.  

Of course this can all be done more rigorously by writing an expression for the equilibrium constant of the reaction and seeing what happens when one of the concentrations is increased.  It is easy to predict that the concentrations of C and D will be increased since making changes in concentrations of any substance has no effect of the equilibrium constant itself.   

Kc   =        [C] [D]
                  [A] [B]

What about temperature changes?
In the case of temperature the problem returns.  If we try to use the wording that involves “oppose” the constraint we can easily obtain the completely incorrect answer.  And I mean completely incorrect as in the case of pressure changes, in the sense of an error of 1800
Consider again the Haber reaction from above but now let’s include the sign of the enthalpy change on going from left to right which is in fact negative to denote an exothermic reaction.  

3 H2      +      N2     <---->      2 NH3     : Delta H = - 92 kJ/mol


How might a student reason?
Let us again put ourselves in the shoes of a novice student trying to innocently use the Le Châtelier Principle in order to predict the outcome of raising the temperature on this system.  The student might reason as follows,

If the temperature of the system is raised and if the outcome is that the system attempts to oppose this change then the system will proceed in the exothermic direction so as to remove the increased heat.  Alas the instructor will immediately point out that this is the incorrect prediction.  Experimental evidence shows clearly that raising the temperature on any exothermic reaction has the effect of favoring the reaction which proceeds in the endothermic rather than the exothermic direction. 

Again, as in the case of pressure changes, the student feels let down by Le Châtelier.  Again in order to rescue the principle many textbooks will cheerfully alter the wording of the principle in order to say that the system will accommodate rather than oppose the change.  If so then they can argue that the additional heat is accommodated by the system’s moving in an endothermic direction, since absorbing the extra heat amounts to accommodating or nullifying the change.  So once again it is not a case of opposing the change but quite the opposite a case of yielding to the change or of accommodating it.


Taking stock 
If what I am saying is correct, then in the three classic changes that are typically considered, namely pressure , concentration and temperature changes, the original Le Châtelier Principle which features the word “oppose” only works in one out of three cases.  That’s not a very good success rate by any stretch of the imagination!

What to do?
My recommendation to textbook authors and chemistry instructors is quite simple.  Please ditch the use of Le Châtelier’s Principle as a guide to what happens when changes are made to chemical systems in equilibrium.  Instead do it rigorously from first principles by setting up expressions for the equilibrium constant and seeing what happens when changes are made to pressure of concentrations of reactants and products.  


Except for temperature changes
Notice that I have omitted temperature changes.  This is because the rigorous approach to temperature changes is different from what it is for pressure or concentration for the simple reason that equilibrium constants actually vary with temperature.  But there are simple thermodynamic expressions which can be used to predict what happens when the temperature is raised or lowered in cases of exothermic or endothermic reactions respectively. 
For example it can be shown that for exothermic reactions the equilibrium constant K is related to temperature in the following manner,

ln K  is proportional to  1/T

from which it follows that as temperature increases the natural logarithm of K decreases and so K itself decreases which implies that the reaction proceeds from right to left rather than the other way round.  Bottom line:  Exothermic reactions are favored by lowering the temperature rather than by raising it.  All this without getting tied up in knots with words and hand waving in trying to use the awful Le Châtelier Principle. 


[i]  I don’t claim to have made a full survey of textbooks but here is an example of the variety in the wording used by a selection of general chemistry books,

•Atkins………………………………..….minimizes
•Chan…………………………………..…relieves
•Petrucci et al……………………..….partially offsets
•Whitten, Davis, Peck…….…….... counteracts
•Moore, Stanitsky, Jurs……………partially counteracts
•Brown, Le May, Bursten……..… counteracts
•Kotz, Trichel……………………..…..reduces or minimizes
•Zumdahl……………………………..…reduces
•Oxtoby, Gillies, Nachtrieb……….counteracts
                                    
Also found, “accommodates” the constraint

Sunday, June 24, 2012

The trouble with using the aufbau to find electronic configurations


Eric Scerri
Department of Chemistry & Biochemistry
UCLA
Los Angeles, CA 90095

website:  http://ericscerri.com

The Periodic Table and the Aufbau
One of the biggest topics in the teaching and learning of chemistry is the use of the aufbau principle to predict the electronic configurations of atoms and to explain the periodic table of the elements.  This method has been taught to many generations of students and is a favorite among instructors and textbooks when it comes to setting questions.  In this blog I am going to attempt to blow the lid off the aufbau because it is deeply flawed, or at least the sloppy version of the aufbau.  The flaw is rather subtle and seems to have escaped the attention of nearly all chemistry and physics textbooks and the vast majority of chemistry professors that I have consulted on the subject.

The error comes from what may be an innocent attempt to simplify matters or maybe just an understandable slip as I will try to explain.  Whatever the cause there is no excuse for perpetuating this educational myth as I will try to explain.

So what’s the problem?
The aufbau method was originally proposed by the great Danish physicist Niels Bohr who was the first to bring quantum mechanics to the study of atomic structure and one of the first to give a fundamental explanation of the periodic table in terms of arrangements of electrons (electronic configurations).  Bohr proposed that we can think of the atoms of the periodic table as being progressively built up starting from the simplest atom of all, that of hydrogen which contains just one proton and one electron.  The other atoms differ from hydrogen by the addition of one proton and one electron.  Helium has two protons and two electrons, lithium has three of each, beryllium has four of each, all the way to uranium which at that time, (1913), was the heaviest known atom, weighing in at 92 protons and 92 electrons.  Neutron numbers vary and are quite irrelevant to this story incidentally.

The next ingredient is a knowledge of the atomic orbitals into which the electrons are progressively placed in an attempt to reproduce the natural sequence of electrons in atoms that occur in the real world.  Oddly enough these orbitals, at least in their simplest form, nowadays come from solving the Schrödinger equation for the hydrogen atom but let’s not get too sidetracked for the moment.

The orbitals
The different atomic orbitals come in various kinds that are distinguished by labels such as s, p, d and f.  Each shell of electrons can be broken down into various orbitals and as we move away from the nucleus each shell contains a progressively larger number of kinds of orbitals.  Here is the well-known scheme,

First shell contains                            1s orbital only
Second shell contains                       2s and 2p orbitals
Third shell contains                          3s, 3p and 3d orbitals
Fourth shell contains                        4s, 4p, 4d and 4f orbitals and so on.

The next part is that one needs to know how many of these orbitals occur in each shell.  The answer is provided by the simple formula 2(l+ 1) where l takes different values depending on whether we are speaking of s, p, d or f orbitals.

For s orbitals l = 0, for p orbitals l = 1, for d orbitals l = 2 and so on.

As a result there are potentially one s orbital, three p orbitals, five d orbitals, seven f orbitals and so on for each shell.

So far so good.  Now comes the magic ingredient which claims to predict the order of filling of these orbitals and here is where the fallacy lurks.  Rather than filling the shells around the nucleus in a simple sequential sequence, where each shell must fill completely before moving onto the next shell, we are told that the correct procedure is more complicated.   But we are also reassured that there is a nice simple pattern that governs the order of shell and consequently of orbitals filling.

And this is finally the point at which the aufbau diagram, which I am going to claim lies at the heart of the trouble, is trotted out. 


The order of filling is said to be obtained by starting at the top of the diagram and following the arrows pointing downwards and towards the left-hand margin of this diagram.  Following this procedure gives us the order of filling of orbitals with electrons according to this sequence,

1s < 2s < 2p < 3s < 3p < 4s < 3d < 4p < 5s < 4d …

This recipe when combined with a knowledge of how many electrons can be accommodated in each kind of orbital and the number of such available orbital in each shell is now supposed to give us a prediction of the complete electronic configuration of all but about 20 atoms in which further irregularities occur, such as the cases of chromium and copper.  Again I don’t want to get side-tracked and so will concentrate on one of the far more numerous regular configurations.

Some examples
To see how this simplified and ultimately flawed method works let me consider a few examples.  The atom of magnesium has a total of 12 electrons.  Using the method above this means that we obtain an electronic configuration of,

1s2, 2s2, 2p6, 3s2

in beautiful agreement with experiments which can examine the configuration directly through the spectra of atoms.  Let’s look at another example, an atom of calcium which has 20 electrons.  Following the well-known method gives a configuration of,
1s2, 2s2, 2p6, 3s2, 3p6, 4s2

and once again there is perfect agreement with experiments on the spectrum of calcium atoms. 

But now let’s see what happens for the very next atom, namely scandium with its 21 electrons.  According to the time honored aufbau method the configuration should be,

1s2, 2s2, 2p6, 3s2, 3p6, 4s2, 3d1

and indeed it is.  But many books proceed to spoil the whole thing by claiming, not unreasonably perhaps, that the final electron to enter the atom of scandium is a 3d electron when in fact experiments point quite clearly to the fact that the 3d orbital is filled before the 4s orbital.  The correct version can be found in very few textbooks but seems to have been unwittingly forgotten or distorted in many cases by generations of instructors and textbook authors as I mentioned at the outset.  How can such an odd situation arise?

Why the mistake occurs
But how can such an apparently blatant mistake have occurred and taken such root in chemical education circles?  The answer is as interesting as it is subtle.  First of all there is the fact that the overall configuration is in fact correctly given by following the sloppy approach.  But if one asks questions about the order of filling the sloppy approach gives the wrong answer as I have been pointing out.  But even worse, it has led many teachers and textbooks to invent all kinds of contorted schemes in order to explain why even though the 4s orbital fills preferentially (as it does in the sloppy version) it is also the 4s electron that is preferentially ionized to form an ion of Sc+.  Since these contortions are pure inventions I will not waste the reader’s time by looking into them.  They are quite simply incorrect since as a matter of fact, the 4s orbital fills last and consequently, as simple logic dictates, is the first orbital to lose an electron on forming a positive ion. 

What’s the evidence? 
But how can I be so confident in claiming that the vast majority of chemistry teachers, professors and textbook authors have erred in presenting the sloppy version.  The answer is that one can just consider the experimental evidence on the ions of any particular transition metal atom such as scandium, 

Sc3+ (tri-positive ion)                        1s2, 2s2, 2p6, 3s2, 3p6, 3d0, 4s0
Sc2+ (di-positive ion)                         1s2, 2s2, 2p6, 3s2, 3p6, 3d1, 4s0
Sc1+ (mono-positive ion)                  1s2, 2s2, 2p6, 3s2, 3p6, 3d1, 4s1
Sc     (neutral atom)                            1s2, 2s2, 2p6, 3s2, 3p6, 3d1, 4s2

On moving from the Sc3+ ion to that of Sc2+ it is plain to see that the additional electron enters a 3d orbital and not a 4s orbital as the sloppy scheme dictates.  Similarly on moving from this ion to the Sc1+ ion the additional electron enters a 4s orbital as it does in finally arriving at neutral scandium atom or Sc.  Similar patterns and sequences are observed for the subsequent atoms in the periodic table including titatium, vanadium, chromium(with further complications), manganese and so on.

Psychological factors
I have been thinking about what psychological factors contribute to the retention of the sloppy aufbau.  As I already mentioned it does give the correct overall configuration for all but about 20 atoms that show anomalous configurations, such as chromium, copper, molybdenum and many others.

Another factor is that it gives chemistry professors the impression that they really can predict the way in which the atom is built-up starting from a bare nucleus to which electrons are successively added.  Presumably it also gives students the impression that they can make similar predictions and perhaps convinces them of the worthiness of the aufbau and scientific knowledge in general. 

The fact remains that it is not possible to predict the configuration in any of the transition metals, and indeed the lanthanides, or if it comes down to it even the p-block elements.  Let’s go back to scandium.  Contrary to the sloppy aufbau that is almost invariably taught, the 3d orbitals have a lower energy than 4s starting with this element.  If we were to try to predict the way that the electrons fill in scandium we might suppose that the final three electrons after the core argon configuration of

1s2, 2s2, 2p6, 3s2, 3p6

would all enter into some 3d orbitals to give,

1s2, 2s2, 2p6, 3s2, 3p6, 3d3

The observed configuration however is,

1s2, 2s2, 2p6, 3s2, 3p6, 3d1, 4s2


What’s really happening?
This amounts to saying that all three of the final electrons enter 3d but two of them are repelled into an energetically less favorable orbital, the 4s, because the overall result is more advantageous for the atom as a whole.  But this is not something that can be predicted.  Why is it 2 electrons, rather than one or even none?  In cases like chromium and copper just one electron is pushed into the 4s orbital.  In an analogous case from the second transition series, the palladium atom, the competition occurs between the 5s and 4d orbitals.  In this case none of the electrons are pushed up into the 5s orbital and the resulting configuration has an outer shell of [Kr]4d10

None of this can be predicted in simple terms from a rule of thumb and so it seems almost worth masking this fact by claiming that the overall configuration can be predicted, at least as far as the cases in which two electrons are pushed up into the relevant s orbital.  To those who like to present a rather triumphal image of science it is too much to admit that we cannot make these predictions.  The use of the sloppy aufbau seems to avoid this problem since it gives the correct overall configuration and hardly anybody smells a rat.

But why do electrons get pushed up into the relevant s orbital?
Finally, it is natural to now ask why it is that one or two electrons are usually pushed into a higher energy orbital, other than the answer I already gave which is to say that doing so produces a more stable atom overall.  The answer lies in the fact that 3d orbitals are more compact than 4s to consider the first transition, and as a result any electrons entering 3d orbitals will experience greater mutual repulsion. 

The slightly unsettling feature is that although the relevant s orbital can relieve such additional electron-electron repulsion different atoms do not always choose to make full use of this form of sheltering because the situation is more complicated than the way in which I have described it.  After all there is the fact that nuclear charge increases as we move through the atoms.  At the end of the day there is a complicated set of interactions between the electrons and the nucleus as well as between the electrons themselves.  This is what ultimately produces an electronic configuration and contrary to what some educators would wish for, there is no simple qualitative rule of thumb that can cope with this complicated situation.    


Bottom line
There is absolutely no reason for chemistry professors and textbook authors to continue to teach the sloppy version of the aufbau.  Not only does it give false predictions regarding the order of electron filling in atoms but it also causes authors and instructors to tell further educational lies.  They are forced to invent some elaborate explanations in order to undo the error in an attempt to explain why 4s is occupied preferentially (which it is not) but also preferentially ionized which it is.
The sloppy version also implies that the 4s orbital has a lower energy than 3d for all atoms which is not the case, or that the 5s orbital has a lower energy than 4d which is not the case for all atoms and so on.  Similar issues arise in the f-block elements.
It is high time that the teaching of aufbau and electronic configurations were carried out properly in order to reflect the truth of the matter rather than taking a short-cut and compounding it with a further imaginary story.


References
The following references are among the few that give the correct explanation;

S-G. Wang, W. H. E. Schwarz, Angew. Chem. Int. Ed. 2009, 48, 19, 3404–3415.

S. Glasstone, Textbook of Physical Chemistry, D. Van Nostrand, New York, 1946.

D.W. Oxtoby, H.P. Gillis, A. Campion, Principles of Modern Chemistry, Sixth Edition,
Thomson/Brooks Cole, 2007.

General Reference on the Periodic Table
Eric Scerri, A Very Short Introduction to the Periodic Table, Oxford University Press, 2011